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5z^2+59z-12=0
a = 5; b = 59; c = -12;
Δ = b2-4ac
Δ = 592-4·5·(-12)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3721}=61$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-61}{2*5}=\frac{-120}{10} =-12 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+61}{2*5}=\frac{2}{10} =1/5 $
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